Synthetic division is a compact way to divide a polynomial by a linear expression of the form \(x-c\). It uses the polynomial’s coefficients instead of writing every power of x at each step. The result gives a quotient and a remainder.

Start with a polynomial

A polynomial is an expression such as \(2x^3-5x^2-4x+3\). Its variable exponents are nonnegative integers, and its coefficients may be positive, negative, zero, or noninteger real numbers. A polynomial expression becomes part of an equation when it is set equal to something.

The standard synthetic division procedure below applies to division by \(x-c\). For other divisors, polynomial long division is a more general method.

Worked example: divide by x − 3

Divide \(2x^3-5x^2-4x+3\) by \(x-3\).

  1. Use 3. Write the divisor as \(x-c\); here, \(c=3\).
  2. List the coefficients: \(2,-5,-4,3\), in descending order of powers.
  3. Bring down 2. This is the first coefficient of the quotient.
  4. Multiply and add: \(3\times2=6\), then \(-5+6=1\).
  5. Repeat: \(3\times1=3\), then \(-4+3=-1\).
  6. Finish: \(3\times(-1)=-3\), then \(3-3=0\).

\[\begin{array}{r|rrrr}3&2&-5&-4&3\\ &&6&3&-3\\\hline &2&1&-1&0\end{array}\]

The last entry is the remainder. The other entries are the coefficients of a polynomial one degree lower than the original:

\[\text{Quotient}=2x^2+x-1,\qquad\text{remainder}=0.\]

Thus,

\[2x^3-5x^2-4x+3=(x-3)(2x^2+x-1).\]

Expanding the right-hand side verifies every coefficient. Since the remainder is zero, \(x-3\) is a factor and \(x=3\) is a root of the original polynomial.

Missing powers need zero coefficients

Now divide \(x^3-4x+2\) by \(x+2\). Rewrite the divisor as \(x-(-2)\), so use \(-2\). The coefficient list is \(1,0,-4,2\): the zero represents the missing \(x^2\) term.

Bring down 1. Multiplying by \(-2\) and adding successively gives \(-2\), then 0, then 2. The quotient is \(x^2-2x\), and the remainder is 2:

\[x^3-4x+2=(x+2)(x^2-2x)+2.\]

For \(x\ne-2\), the corresponding division can be written as

\[\frac{x^3-4x+2}{x+2}=x^2-2x+\frac2{x+2}.\]

The polynomial identity remains true at \(x=-2\), but the fraction is undefined there because its denominator is zero. There is no general restriction that x must be nonzero.

The remainder theorem

When a polynomial \(P(x)\) is divided by \(x-c\), its remainder is \(P(c)\). In the second example,

\[P(-2)=(-2)^3-4(-2)+2=2,\]

which agrees with the synthetic division result. A remainder of zero means \(x-c\) is a factor; a nonzero remainder means it is not.

Common mistakes

  • Using the wrong sign: divide by \(x+2\) using \(-2\), not 2.
  • Omitting zero placeholders for missing powers.
  • Reading the final remainder as another quotient coefficient.
  • Applying the basic procedure unchanged to a divisor such as \(2x-3\).

Continue with factoring or the quadratic formula when the quotient needs further analysis.

Further reading

OpenStax covers both polynomial long division and synthetic division.